Destide@feddit.uk to Programmer Humor@lemmy.mlEnglish · 1 month agoInfallible Codeimagemessage-square143linkfedilinkarrow-up1474arrow-down126
arrow-up1448arrow-down1imageInfallible CodeDestide@feddit.uk to Programmer Humor@lemmy.mlEnglish · 1 month agomessage-square143linkfedilink
minus-squareredxef@feddit.orglinkfedilinkarrow-up38·1 month agodef is_even(n: int) -> bool: if n < 0: return is_even(-n) r = True for _ in range(n): r = not r return r
minus-squareOddMinus1@sh.itjust.workslinkfedilinkarrow-up4·edit-21 month agoCould also be done recursive, I guess? boolean isEven(int n) { if (n == 0) { return true; } else { return !isEven(Math.abs(n - 1)); } }
minus-squaredragonlobster@programming.devlinkfedilinkarrow-up2·1 month agoHe loves me, he loves me not
minus-squarevandsjov@feddit.dklinkfedilinkarrow-up1·1 month agoNo, no, I would convert the number to a string and just check the last char to see if it was even or not.
def is_even(n: int) -> bool: if n < 0: return is_even(-n) r = True for _ in range(n): r = not r return rCould also be done recursive, I guess?
boolean isEven(int n) { if (n == 0) { return true; } else { return !isEven(Math.abs(n - 1)); } }deleted by creator
He loves me, he loves me not
No, no, I would convert the number to a string and just check the last char to see if it was even or not.